###### 1

\(y=x^2+4x-12\)

The vertex of the parabola is \((-2,16)\text{.}\) The axis of symmetry is the line with equation \(x=-2\text{.}\) The parabola is concave up. The \(x\)-intercepts are \((-6,0)\) and \((2,0)\text{.}\) The \(y\)-intercept is \((0,-12)\text{.}\)