###### Example6.2.2

Determine the \(x\)-intercept of the line with equation \(-11x+5y=-110\text{.}\)

Since the \(x\)-intercept is a point on the \(x\)-axis, it must have a \(y\)-coordinate of zero. Replacing \(y\) with zero and solving for \(x\) results in \(x=10\text{.}\) So the \(x\)-intercept of the line is the point \((10,0)\text{.}\)