Whenever \(\lim\limits_{x \to a}\fe{f}{x} \neq 0\) but \(\lim\limits_{x \to a}\fe{g}{x} = 0\text{,}\) then \(\lim\limits_{x \to a}\frac{\fe{f}{x}}{\fe{g}{x}}\)does not exist because from either side of \(a\) the value of \(\frac{\fe{f}{x}}{\fe{g}{x}}\) has an absolute value that will become arbitrarily large. In these situations the line \(x = a\) is a vertical asymptote for the graph of \(y = \frac{\fe{f}{x}}{\fe{g}{x}}\text{.}\) For example, the line \(x = 2\) is a vertical asymptote for the function \(h\) defined by \(\fe{h}{x} = \frac{x+5}{2-x}\text{.}\) We say that \(\lim\limits_{x \to 2}\frac{x+5}{2-x}\) has the form βnot-zero over zero.β (Specifically, the form of \(\lim\limits_{x \to 2}\frac{x+5}{2-x}\) is \(\frac{7}{0}\text{.}\)) Every limit with form βnot-zero over zeroβ does not exist. However, we frequently can communicate the non-existence of the limit using an infinity symbol. In the case of \(\fe{h}{x} = \frac{x+5}{2-x}\) itβs pretty easy to see that \(\fe{h}{1.99}\) is a positive number whereas \(\fe{h}{2.01}\) is a negative number. Consequently, we can infer that \(\lim\limits_{x \to 2^{-}}\fe{h}{x} = \infty\) and \(\lim\limits_{x \to 2^{+}}\fe{h}{x} = -\infty\text{.}\) Remember, these equations are communicating that the limits do not exist as well as the reason for their non-existence. There is no short-hand way to communicate the non-existence of the two-sided limit \(\lim\limits_{x \to 2}\fe{h}{x}\text{.}\)
Use this as an opportunity to discuss why limits of form βnot-zero over zeroβ are βinfinite limits.β What limit equation is being illustrated in the table?
Hear me, and hear me loudβ¦\(\infty\)does not exist. This, in part, is why we cannot apply Limit Law R1 to an expression like \(\lim\limits_{x \to \infty}x\) to see that \(\lim\limits_{x \to \infty}x = \infty\text{.}\) When we write, say, \(\lim\limits_{x \to 7}x = 7\text{,}\) we are replacing the limit expression with its valueβthatβs what the replacement laws are all about! When we write \(\lim\limits_{x \to \infty}x = \infty\text{,}\) we are not replacing the limit expression with a value! We are explicitly saying that the limit has no value (i.e. does not exist) as well as saying the reason the limit does not exist. The limit laws can only be applied when all of the limits in the equation exist. With this in mind, discuss and decide whether each of the following equations is true or false.
Mindy tried to evaluate \(\lim\limits_{x \to 6^{+}}\frac{4x-24}{x^2 - 12x + 36}\) using the limit laws. Things went horribly wrong for Mindy (her work is shown below). Identify what is wrong in Mindyβs work and discuss what a more reasonable approach might have been. This βsolutionβ is not correct! Do not emulate Mindyβs work!