The derivative chain can be expressed backwards as well as forwards. When you move from function to function in the reverse direction the resultant functions are called antiderivatives and the process is called antidifferentiation. These relationships are shown in FiguresΒ 4.5.1 and 4.5.2.
When you differentiate, the resultant function is unique. When you antidifferentiate, you do not get a unique functionβyou get a family of functions; specifically, you get a set of parallel curves.
We introduce a new function in the antidifferentiation chain. We say that \(F\) is an antiderivative of \(f\text{.}\) This is where we stop in that direction; we do not have a variable name for an antiderivative of \(F\text{.}\)
Since \(F\) is considered an antiderivative of \(f\text{,}\) it must be the case that \(f\) is the first derivative of \(F\text{.}\) Hence we can add \(F\) to our derivative chain resulting in FigureΒ 4.5.3.
Draw onto the second figure the continuous antiderivative of \(f\) that passes through the point \(\point{-3}{1}\text{.}\) Note that every antiderivative of \(f\) increases exactly one unit over the interval \(\ointerval{-3}{-2}\text{.}\)
Because \(f\) is not continuous, there are other antiderivatives of \(f\) that pass through the point \(\point{-3}{1}\text{.}\) Specifically, antiderivatives of \(f\) may or may not be continuous at \(-1\text{.}\) Draw onto the third and fourth figures different antiderivatives of \(f\) that pass through the point \(\point{-3}{1}\text{.}\)
Recall that a function, \(f\text{,}\) is periodic if there exists a nonzero constant, \(C\text{,}\) with the property that \(\fe{f}{x+C} = \fe{f}{x}\) for all values of \(x\) in the domain of \(f\text{.}\) The function \(y = \fe{\sin}{x}\) is an example of a periodic function. Specifically, the function has a period of \(2\pi\) because over any interval of length \(2\pi\) the behavior of the function is exactly the same as it was over the previous interval of length \(2\pi\text{.}\) A little more precisely, \(\fe{\sin}{x+2\pi} = \fe{\sin}{x}\) regardless of the value of \(x\text{.}\)
Jasmine was thinking and told her lab assistant that derivatives and antiderivatives of periodic functions must also be periodic. Jasmineβs lab assistant told her that she was half right. Which half did Jasmine have correctβthe part about the derivatives necessarily being periodic or the part about antiderivatives necessarily being periodic? Also, draw a function that illustrates that the other half of Jasmineβs statement is not correct.
Let \(G\) be an antiderivative of \(g\text{.}\) Suppose that \(G\) is continuous on \(\cinterval{-6}{6}\text{,}\)\(\fe{G}{-6} = -3\text{,}\) and that the greatest value \(G\) ever achieves is \(6\text{.}\) Draw \(G\) onto FigureΒ 4.5.5.
Answer the following questions in reference to a continuous function \(g\) whose first derivative is shown in the figure. You do not need to state how you made your determination; just state the interval(s) or values of \(x\) that satisfy the stated property. Note: the correct answer to one or more of these questions may be βThere is no way of knowing.β