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Activity 3.5 Supplement

Find the first derivative formula for each of the following functions twice: first by evaluating \(\lim\limits_{h\to0}\frac{\fe{f}{x+h}-\fe{f}{x}}{h}\) and then by evaluating \(\lim\limits_{t\to x}\frac{\fe{f}{t}-\fe{f}{x}}{t-x}\text{.}\)

1.

\(\fe{f}{x}=x^2\)

2.

\(\fe{f}{x}=\sqrt{x}\)

3.

\(\fe{f}{x}=7\)

4.

It can be shown that \(\lim\limits_{h\to0}\frac{\fe{\sin}{h}}{h}=1\) and \(\lim\limits_{h\to0}\frac{\fe{\cos}{h}-1}{h}=0\text{.}\) Use these limits to help you to establish the first derivative formula for \(\fe{\sin}{x}\text{.}\)

Hint

Begin with \(\lim\limits_{h\to0}\frac{\fe{\sin}{x+h}-\fe{\sin}{x}}{h}\) and use the angle addition formula for \(\fe{\sin}{x+h}\text{.}\)

Suppose that an object is tossed into the air in such a way that the elevation of the object (measured in ft) \(t\) seconds after the object was tossed is given by the function \(\fe{s}{t}=150+60t-16t^2\text{.}\)

5.

Find the velocity function for this motion and use it to determine the velocity of the object \(4.1\) s into its motion.

6.

Find the acceleration function for this motion and use that function to determine the acceleration of the object \(4.1\) s into its motion.

Determine the unit on the first derivative function for each of the following functions. Remember, we do not simplify derivative units in any way, shape, or form.

7.

\(\fe{R}{p}\) is Carl's heart rate (beats per min) when he jogs at a rate of \(p\) (measured in ftmin).

8.

\(\fe{F}{v}\) is the fuel consumption rate galmi of Hanh's pick-up when she drives it on level ground at a constant speed of \(v\) (measured in mih).

9.

\(\fe{v}{t}\) is the velocity of the space shuttle mih where \(t\) is the amount of time that has passed since liftoff (measured in s).

10.

\(\fe{h}{t}\) is the elevation of the space shuttle (mi) where \(t\) is the amount of time that has passed since lift-off (measured in s).

Referring to the functions in Exercises 3.5.7–10, write sentences that explain the meaning of each of the following function values.

11.

\(\fe{R}{300}=84\)

12.

\(\fe{\fd{R}}{300}=0.02\)

13.

\(\fe{F}{50}=0.03\)

14.

\(\fe{\fd{F}}{50}=-0.0006\)

15.

\(\fe{v}{20}=266\)

16.

\(\fe{\fd{v}}{20}=18.9\)

17.

\(\fe{h}{20}=0.7\)

18.

\(\fe{\fd{h}}{20}=0.074\)

It can be shown that the derivative formula for the function \(f\) defined by \(\fe{f}{x}=\frac{2x^3+2x+1}{3+5x^2}\) is \(\fe{\fd{f}}{x}=\frac{10x^4+8x^2-10x+6}{25x^4+30x^2+9}\text{.}\)

19.

Determine the equation of the tangent line to \(f\) at \(1\text{.}\)

20.

A graph of \(f\) is shown in Figure 3.5.1; axis scales have deliberately been omitted from the graph.

The graph shows that \(f\) quickly resembles a line. In a detailed sketch of \(f\) we would reflect this apparent linear behavior by adding a skew asymptote. What is the slope of this skew asymptote?

Figure 3.5.1. \(y=\fe{f}{x}=\frac{2x^3+2x+1}{3+5x^2}\)