Skip to main content

Worksheet 1.5 Networks Worksheet (No Theorems, No Examples)

Basic laws for electrical circuits.

This two-page worksheet was generously donated to the sample article by Virgil Pierce at a CuratedCourses workshop in AugustĀ 2018.

Ohms Law.

The current through a resistor is proportional to the ratio of the Voltage to the Resistance

\begin{equation*} I = \frac{V}{R}\qquad\text{or for our purposes,}\qquad I R = V \end{equation*}
Kirchoffs Current Law.

The sum of the currents in a network meeting at a point is zero.

\begin{equation*} \sum_{k=1}^n I_k = 0 \end{equation*}

For example, in the circuit below, \(I_1 + I_2 = I_3 \text{.}\)

Kirchoffs Voltage Law.

The sum of the voltages around any closed circuit (or subcircuit) is zero.

\begin{equation*} \sum_{k=1}^n V_k = 0 \end{equation*}

Kirchoffs Current Law and Kirkoffs Voltage Law combined with Ohms Law gives for any circuit of resistors and sources a linear system that may (or may not) determine the currents.

1.

For the simple network pictured, calculuate the amperage in each part of the network by setting up a system of linear equations for the amperages.

2.

Compare it to a parallel circuit network. Calculate the amperage in each part of the network by setting up a system of linear equations for the amperages.


3.

Now for a more complicated network. Calculate the amperage in each part of the network by setting up a system of linear equations for the amperages.

4.

Now generalize these ideas to a context outside of electrical circuits. Consider the network of streets given in the diagram (with one-way directions as indicated).

A traffic engineer counts the hourly flow of cars into and out of this network at the entrances. They get (EB = East Bound; WB = West Bound):

Table 1.5.1. Estimated hourly traffic flow for the road network
EB Winooski WB Winooski Shelburne St Willow Jay
into 50 400 0 10 50
out of 55 390 20 15 30

Use a variable for each segment inside of the network and set up a system of linear equations restricting the flow. Solve the system. Note that you should not get a unique solution as traffic should be able to flow through the network in various ways.