I[JS,dd   1Courier NewSymbolew Roman1Courier New1Courier NewTimes New RomanTimes New Roman1Courier New1Courier New1Courier New1Courier New0:Q<0:Q<0:Q<0:Q<{ d< p {(\?̬?̬̬?(\????@@@@@@033333??@^ߛOw?̌???H:@`H`j`j@@?@ @@@$[L?@@2??@????????\w;a? $(,H&Bԣaaٳ?u@ d 1-(x^2+y^2) x^2+y^2=1PP2??@`eUR?^Ф??????? $(,0`HX00cos(pi/3+.04)sin(pi/3+.04)+seg (0,0) to (cos(pi/3+.04),sin(pi/3+.04))PP2???$$$`eUR?^Ф?????????`eUR?^Ф?48<@DHLxcos(pi/3+.04)sin(pi/3+.04)pi/4&(x,y) = (cos(pi/3+.04),sin(pi/3+.04))PPd2??h!@$$$J{/L ????????PTX\`dh$@|h4.21#r = .21; 0.000000 <= t <= 1.0472002???$$$׽?u˜??????? lptx|x؛$00 cos(.476) sin(.476)#seg (0,0) to (cos(.476),sin(.476))\2???$$$׽?u˜?????????׽?u˜? K$x cos(.476) sin(.476)pi/4(x,y) = (cos(.476),sin(.476)).5hўd2??h!@$$$ʡE???????? plLl.3"r = .3; 0.000000 <= t <= 0.4760002???$$$nOұ?@2(???????8<6789:L=|qLt00cos(pi/4+.0175)sin(pi/4+.0175)/seg (0,0) to (cos(pi/4+.0175),sin(pi/4+.0175))2???$$$nOұ?@2(?????????nOұ?@2(?z{,048<egcos(pi/4+.0175)sin(pi/4+.0175)pi/4*(x,y) = (cos(pi/4+.0175),sin(pi/4+.0175))2??h!@$$$Cl????????h@DHLPT|y,zx(.45#r = .45; 0.000000 <= t <= 0.789000xyzJXT@&Bԣaaٳ?@@@@@@@@@@@@@@@@@@@@@@@@@@@ H H H x^2+y^2=18T@/- `?seg (0,0) to (cos(pi/3+.04),sin(pi/3+.04))))pܪ@1q!t?(x,y) = (cos(pi/3+.04),sin(pi/3+.04)))1Ppܪ?4333333Pʭ?r = .21; 0.000000 <= t <= 1.047200pܪ?4333333" ?Dseg (0,0) to (cos(.476),sin(.476))*#pܪ̬?Y?(x,y) = (cos(.476),sin(.476))pܪ̬?`#fr = .3; 0.000000 <= t <= 0.476000pܪ033333?x=seg (0,0) to (cos(pi/4+.0175),sin(pi/4+.0175))pܪ̬?$^}W?X(x,y) = (cos(pi/4+.0175),sin(pi/4+.0175))pܪ̬?mP0U( r = .45; 0.000000 <= t <= 0.789000pܪ̬?B"