Exercise5

Is \(-1\) a solution for \(x\) in the equation \({2x-1}={4-\left(8+x\right)}\text{?}\) Evaluating the left and right sides gives:

\({2x-1}\) \(=\) \({4-\left(8+x\right)}\)
\({}\stackrel{?}{=}{}\)

So \(-1\)

a solution to \({2x-1}={4-\left(8+x\right)}\text{.}\)

in-context