###### Exercise 48

Solve this inequality.

\(\displaystyle{ {-\frac{z}{12}} \lt {-\frac{3}{4}} }\)

In set-builder notation, the solution set is .

In interval notation, the solution set is .

Solve this inequality.

\(\displaystyle{ {-\frac{z}{12}} \lt {-\frac{3}{4}} }\)

In set-builder notation, the solution set is .

In interval notation, the solution set is .