Exercise 53

A rectangular frame’s perimeter is \(6\) feet. If its length is \(2\) feet, suppose we want to find how long is its width. A rectangle’s perimeter formula is

\begin{equation*} P=2(l+w) \end{equation*}

where \(P\) stands for perimeter, \(l\) for length and \(w\) for width. We can solve this problem using the equation:

\begin{equation*} 6=2(2+w) \end{equation*}

Check whether \(4\) is a solution for \(w\) of this equation.