Exercise 42

A triangle’s area is \(95\) square meters. Its height is \(10\) meters. Suppose we wanted to find how long is the triangle’s base. A triangle’s area formula is

\begin{equation*} A=\frac{1}{2}bh \end{equation*}

where \(A\) stands for area, \(b\) for base and \(h\) for height. If we let \(b\) be the triangle’s base, in meters, we can solve this problem using the equation:

\begin{equation*} {95}=\frac{1}{2}(b)(10) \end{equation*}

Check whether \(38\) is a solution for \(b\) of this equation.