###### Example 2.4.11 Cylinder Volume

A cylinder's volume is related to its radius and its height by:

\begin{equation*}
V=\pi r^2h\text{,}
\end{equation*}

where \(V\) is the volume, \(r\) is the base's radius, and \(h\) is the height. If we know the volume is 96\(\pi\) cm^{3} and the radius is 4 cm, then we have:

\begin{equation*}
96\pi=16\pi h
\end{equation*}

Is 4 cm the height of the cylinder? In other words, is \(4\) a solution to \(96\pi=16\pi h\text{?}\) We will substitute \(h\) in the equation with \(4\) to check:

\begin{align*}
96\pi\amp=16\pi h\\
96\pi\amp\stackrel{?}{=}16\pi \cdot\substitute{4}\\
96\pi\amp\stackrel{\text{no}}{=}64\pi
\end{align*}

Since \(96\pi=64\pi\) is false, \(h=4\) does *not* satisfy the equation \(96\pi=16\pi h\text{.}\)

Next, we will try \(h=6\text{:}\)

\begin{align*}
96\pi\amp=16\pi h\\
96\pi\amp\stackrel{?}{=}16\pi \cdot\substitute{6}\\
96\pi\amp\stackrel{\checkmark}{=}96\pi
\end{align*}

When \(h=6\text{,}\) the equation \(96\pi=16\pi h\) is true. This tells us that \(6\) *is* a solution to \(96\pi=16\pi h\text{.}\)